By Syed Nasar

ISBN-10: 0070459363

ISBN-13: 9780070459366

Schaum’s robust problem-solver delivers 3,000 difficulties in electrical circuits, totally solved step by step! The originator of the solved-problem consultant, and scholars’ favourite with over 30 million learn courses bought, Schaum’s bargains a diagram-packed timesaver that will help you grasp all types of challenge you’ll face on assessments.

difficulties hide each quarter of electrical circuits, from easy devices to complicated multi-phase circuits, two-port networks, and using Laplace transforms. pass on to the solutions and diagrams you would like with our precise, cross-referenced index. appropriate with any school room textual content, Schaum’s 3000 Solved difficulties in electrical Circuits is so entire it’s the fitting device for graduate or expert examination prep!

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**Additional resources for 3000 Solved Problems in Electrical Circuits**

**Sample text**

3-34, for the given values of R 4, R s' and R6 as in Prob. 94, and for the respective calculated values of RI' R 2, and R 3, find the volta;~e across R 3· I From the data of Prob. 5) . 5 0, and R6 = 60 in Fig. 3-34, find the voltage across R3 with S open for the values of RI' R 2• and R3 calculated in Prob. 97. I Proceeding as in Prob. 09 V Define: . (no· load voltage) - (voltage on load) Vio Itage regulatIon =: ----. voltage on load Calculate the voltage regulation from the results I Probs. 99.

Verify that the sum of the power losses is the same as the power delivered by the source. ~;9 A I LP lOSS V= ! 85 15 = 16 = = 120 x 40 = 4800 W Figure 3-28a shows a ladder network. 022% From the data, determine the voltage Vx and the current Ix' I The circuit reduction is shown in Fig. 3-28b thro~gh e. P From Fig. ::..... =2A 4+2 From Fig. 3-28d: 6 I = ---- 2 = 1 333 A From Fig. 3-28b: Ix = 3! 667 A = 13 From Fig. 0 V I 6+ 3 . ~'~;f ,3 <... E] "f +(1. (t- 1~~ Fs~ b) I 2. L1(q) Fig. n.. 86 D 35 Solve Prob.

80 How much power is drawn from the battery if the 6-0 resistor of the circuit of Fig. 3-26a is open-circuited? I In this case the equivalent resistance R = 1 + 3(2 + 4) = 3 0 3+2+4 Power drawn from the battery is 15 x 5 = 75 W. 81 A resistive circuit is shown in Fig. 3-27a. R = 15 = 5 A 3 Determine the equivalent resistance R. I The circuit reductions are shown in Fig. ::': thus 3-27b through d, from which R = 1 + 2 = 3 O. fl. I I. 17... - 14- VIfI ~ (,f2.. (L.. >+£ - 2 1,.. J ------------------------~ (ri) Fig.

### 3000 Solved Problems in Electrical Circuits by Syed Nasar

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